杰理-watch-手表-AC701-双击屏幕唤醒 TP不在休眠状态,功耗较大,测试熄屏功耗2-3mA (1)TP抬起的时候rouse_two_flag置1 判断是都开启双击唤醒,关闭TP则进入睡眠,功耗降低 开机设定初始状态 static bool double_rouse_flag = 0; 函数:static int list_luminance_set_ontouch_G(void *ctr, struct element_touch_event *e) 2022-10-20-补充(滑动不许唤醒) static bool Double_Rouse_flag = 0;