递归判断JS对象内所有属性值是否为空，并返回空值的key和value

代码

const paramsValidate = (obj: any, ...roles: Array<Array<string>>) => {let currentKey:Array<string> = [] // 当前的Keylet unValidateKeyArr:Map<Array<string>, string> = new Map() // 未通过的Keyconst valNull = (obj: any) => {for(let k in obj) {    if(obj[k] instanceof Object) {currentKey.push(k)valNull(obj[k])currentKey.pop()} currentKey.push(k)// 判定空值const valueRule = obj[k] === undefined || obj[k] === null || obj[k] === ''// 判断空对象，空数组const objRule = obj[k] instanceof Object && Object.keys(obj[k]).length === 0// 判定是否跳过该条件const customRole = !roles.find(role => {return JSON.stringify(role) === JSON.stringify(currentKey)})if((valueRule || objRule) && customRole) {unValidateKeyArr.set(currentKey.slice(), obj[k])}currentKey.pop()}return unValidateKeyArr}return valNull(obj)
}

测试用例

let o = {name: "张三Z", age: undefined,school: null,idCard: { id: '', img: ''},id: '',arr: [],t: {}
}
const valrs = paramsValidate(o, ['idCard','id'])
console.log(valrs)

运行结果：

Map(6) {[ 'age' ] => undefined,[ 'school' ] => null,[ 'idCard', 'img' ] => '',[ 'id' ] => '',[ 'arr' ] => [],[ 't' ] => {}
}