A1065 A+B and C (64bit)

news/2024/11/24 6:10:04/

1065 A+B and C (64bit) (20 分)

Given three integers A, B and C in [−2^{63}​​,2^{63}], you are supposed to tell whether A+B>C.

Input Specification:

The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false
#include <cstdio>
using namespace std;int main()
{int t, num = 0;long long a, b, c;scanf("%d", &t) ;while(t--){scanf("%lld%lld%lld", &a, &b, &c);long long sum = a + b;bool flag;if(a>0 && b>0 && sum<0) flag = true;else if(a<0 && b<0 && sum>=0) flag = false;else if(sum > c) flag = true;else flag = false;if(flag == true){printf("Case #%d: true\n", ++num);}else {printf("Case #%d: false\n", ++num);}}return 0;
}

 


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