问题：

python循环时循环体发生改变？

解决办法一

有时候在项目中我们遇到了循环体一直在改变怎么去循环？想到一个办法，记录下来，下次遇到直接上代码就可以。

# 循环一次获取一次
import random
xinghao_name = []
for i in range(1000):# 点击型号poco(text="型号").wait_for_appearance(20)poco(text="型号").click()sleep(random.uniform(1.8,3.2))pinpai_1 = poco("android.widget.FrameLayout").offspring("com.wuba.zhuanzhuan:id/fai").child("android.webkit.WebView").child("android.webkit.WebView").child("android.view.View")[0].child("android.view.View")[1].child("android.view.View").child("android.view.View")[1].child("android.view.View")[1].child("android.view.View").child("android.view.View")[1].child("android.view.View")[i]if pinpai_1.child("android.view.View"):xinghao_txt = pinpai_1.child("android.view.View").get_text()# 查看更多时，选择走这个if "查看更多" in xinghao_txt:poco(text="查看更多").click()pinpai_1 = poco("android.widget.FrameLayout").offspring("com.wuba.zhuanzhuan:id/fai").child("android.webkit.WebView").child("android.webkit.WebView").child("android.view.View")[0].child("android.view.View")[1].child("android.view.View").child("android.view.View")[1].child("android.view.View")[1].child("android.view.View").child("android.view.View")[1].child("android.view.View")[i]xinghao_txt = pinpai_1.child("android.view.View").get_text()print(xinghao_txt)xinghao_name.append(xinghao_txt)pinpai_1.click()
#         poco(text="型号").wait_for_appearance(20).click().children().get_text()print(xinghao_name)