描述
Customers 表有字段,顾客名称:cust_name、顾客id:cust_id
cust_id | cust_name |
cust10 | andy |
cust1 | ben |
cust2 | tony |
cust22 | tom |
cust221 | an |
cust2217 | hex |
Orders订单信息表,含有字段,订单号:order_num、顾客id:cust_id
order_num | cust_id |
a1 | cust10 |
a2 | cust1 |
a3 | cust2 |
a4 | cust22 |
a5 | cust221 |
a7 | cust2217 |
OrderItems表有字段,商品订单号:order_num、商品数量:quantity、商品价格:item_price
order_num | quantity | item_price |
a1 | 1000 | 10 |
a2 | 200 | 10 |
a3 | 10 | 15 |
a4 | 25 | 50 |
a5 | 15 | 25 |
a7 | 7 | 7 |
【问题】
除了返回顾客名称和订单号,返回 Customers 表中的顾客名称(cust_name)和Orders 表中的相关订单号(order_num),添加第三列 OrderTotal,其中包含每个订单的总价,并按顾客名称再按订单号对结果进行升序排序。
【示例结果】返回顾客名称 cust_name、订单号order_num、订单总额OrderTotal
cust_name | order_num | OrderTotal |
an | a5 | 375 |
andy | a1 | 10000 |
ben | a2 | 2000 |
hex | a7 | 49 |
tom | a4 | 1250 |
tony | a3 | 150 |
【示例解析】
例如顾客名称cust_name为an的顾客的订单a5的订单总额为quantity*item_price = 15 * 25 = 375,最后以cust_name和order_num来进行升序排序。
示例1
输入:
DROP TABLE IF EXISTS `Orders`; CREATE TABLE IF NOT EXISTS `Orders`(order_num VARCHAR(255) NOT NULL COMMENT '商品订单号',cust_id VARCHAR(255) NOT NULL COMMENT '顾客id' ); INSERT `Orders` VALUES ('a1','cust10'),('a2','cust1'),('a3','cust2'),('a4','cust22'),('a5','cust221'),('a7','cust2217');DROP TABLE IF EXISTS `Customers`; CREATE TABLE IF NOT EXISTS `Customers`(cust_id VARCHAR(255) NOT NULL COMMENT '客户id',cust_name VARCHAR(255) NOT NULL COMMENT '客户姓名' ); INSERT `Customers` VALUES ('cust10','andy'),('cust1','ben'),('cust2','tony'),('cust22','tom'),('cust221','an'),('cust2217','hex');DROP TABLE IF EXISTS `OrderItems`; CREATE TABLE IF NOT EXISTS `OrderItems`(order_num VARCHAR(255) NOT NULL COMMENT '商品订单号',quantity INT(16) NOT NULL COMMENT '商品数量',item_price INT(16) NOT NULL COMMENT '商品价格' ); INSERT `OrderItems` VALUES ('a1',1000,10),('a2',200,10),('a3',10,15),('a4',25,50),('a5',15,25),('a7',7,7);
复制输出:
an|a5|375 andy|a1|10000 ben|a2|2000 hex|a7|49 tom|a4|1250 tony|a3|150
复制
《SQL必知必会(第5版)》独家授权
答案
select t1.cust_name,t2.order_num,sum(t3.quantity*t3.item_price) as orderTotal
from Customers t1,Orders t2,OrderItems t3
where t1.cust_id=t2.cust_id
and t2.order_num=t3.order_num
group by t1.cust_name,t2.order_num
order by t1.cust_name,t2.order_num