前言
嗨喽~大家好呀，这里是魔王呐 ❤ ~!
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方法一：for in循环
from random import randint, samplea1 = {k: randint(1, 4) for k in 'abcdefg'}
a2 = {k: randint(1, 4) for k in 'abc123456789'}
a3 = {k: randint(1, 4) for k in 'abcinubububu'}
a4 = {k: randint(1, 4) for k in 'abc89898989'}
r = []for x in a1:if x in a2 and x in a3 and x in a4:r.append(x)
print(r)
randint(1, 4) # 从1~4间随机取一个数
方法二：利用集合的交集操作
'''
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'''
from random import randint, samplea1 = {k: randint(1, 4) for k in 'abcdefg'}
a2 = {k: randint(1, 4) for k in 'abcdefg'}
a3 = {k: randint(1, 4) for k in 'abcdefg'}
a4 = {k: randint(1, 4) for k in 'abcdefg'}a = a1.keys() & a2.keys() & a3.keys() & a4.keys()
print(a)
a1.keys()：得到a1字典的key，一set格式；
a1.keys() & a2.keys() & a3.keys() & a4.keys()：取4个集合的公共元素；
a为一个集合（set）
方法三：使用map即reduce（用于求n个字典的公共key）
from random import randint, sample
from functools import reducea1 = {k: randint(1, 4) for k in 'abcdefg'}
a2 = {k: randint(1, 4) for k in 'abcdefg'}
a3 = {k: randint(1, 4) for k in 'abcdefg'}
a4 = {k: randint(1, 4) for k in 'abcdefg'}b1 = map(dict.keys, [a1, a2, a3, a4])
b2 = reduce(lambda a ,b: a & b, b1)print(b2)b1 = map(dict.keys, [a1, a2, a3, a4]) #以集合形式取每个字典的keys；
尾语
最后感谢你观看我的文章呐~本次航班到这里就结束啦 🛬
希望本篇文章有对你带来帮助 🎉，有学习到一点知识~
躲起来的星星🍥也在努力发光，你也要努力加油（让我们一起努力叭）。
