交互式问题要关闭ios，要不然完蛋！！！！！！！！！！！！！！！！！！（没有输出） 

#include<bits/stdc++.h>
using namespace std;
#define ll long long
const int N=1e5+10;
int check(int x,int y){int s;cin>>s;if((x+1)*(y+1)==s){ return 1;}else if((x)*(y+1)==s){return 0;}else if(x*y==s){return -1;}
}
void Solve(){int l=2,r=999;while(r-l>=2){int mid1=l+(l+r)/3,mid2=r-(l+r)/3;cout<<"? "<<mid1<<" "<<mid2<<endl;int pos=check(mid1,mid2);if(pos==1){r=mid1;}else if(pos==0){l=mid1+1,r=mid2;}else{l=mid2+1;}}if(l!=r){cout<<"? "<<l<<" "<<r<<endl;if(check(l,r)==1) cout<<"! "<<l<<endl;else cout<<"! "<<r<<endl;}else cout<<"! "<<l<<endl;}   
int main(){//ios::sync_with_stdio(0);//cin.tie(0);cout.tie(0);int T=1;cin>>T;while(T--){Solve();}return 0;
}

#include <bits/stdc++.h>using namespace std;
typedef long long ll;
typedef double db;
typedef long double ldb;
typedef pair<int, int> pii;
typedef pair<ll, ll> PII;
#define pb emplace_back
//#define int ll
#define all(a) a.begin(),a.end()
#define x first
#define y second
#define ps push_back
#define endl '\n'
#define IOS ios::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#define lc u << 1
#define rc u << 1 | 1void solve();const int N = 1e6 + 10;signed main() {
//    IOS;ll t = 1;cin >> t;while (t--)solve();return 0;
}ll q(ll mid)
{cout << "? " << 1 << ' ' << mid << endl;ll res; cin >> res;return res;
}void solve() {ll l = 2, r = 999;while(l < r){ll mid = (l + r) >> 1;if(q(mid) == mid + 1){r =  mid;}elsel = mid + 1;}cout << "! " << l << endl;
}