一道SQL题

news/2024/11/17 5:56:15/

有个搞数仓的朋友不知道从哪儿弄了个题。。。
做了做体验了一下。。。
记录记录。
在这里插入图片描述

分析

要保证每天都要做新题
5天必须都做题，不然GG
最后一天必须做新题，如果最后一天做新题了，前面那几天没做新题，做的是老题

最后一天，如果没做题会被踢出
最后一天做的题，不是新题记录0，当求和之后为0，说明没有新题，那就踢出
如果是最后一天做了新题，第四天没做新题

下面的问题需要处理，

用户a，前四天（1，2，3）
第一天：1，2，3
第二天：1，2，3
第三天：1，2，3
第四天：1，2，3

第五天：1，2，3，4

保证最后一天做新题的案例：

SELECTinfo.user_id 
FROM
(SELECTtwo.user_id,sum(IF(two.question_id IN ( SELECT DISTINCT one.question_id FROM log_table AS one WHERE one.date between "2022-09-19" and "2022-09-22" AND one.user_id = two.user_id ),0,1 )) AS num FROMlog_table AS two WHEREtwo.date = "2022-09-23"GROUP BYtwo.user_id ) info 
WHEREinfo.num >0

补充完善

select* 
from (SELECTinfo.user_id 
FROM
(SELECTtwo.user_id,sum(IF(two.question_id IN ( SELECT DISTINCT one.question_id FROM log_table AS one WHERE one.date between "2022-09-19" and "2022-09-22" AND one.user_id = two.user_id ),0,1 )) AS num FROMlog_table AS two WHEREtwo.date = "2022-09-23"GROUP BYtwo.user_id ) info 
WHEREinfo.num >0) as d5 
left join (SELECTinfo.user_id 
FROM
(SELECTtwo.user_id,sum(IF(two.question_id IN ( SELECT DISTINCT one.question_id FROM log_table AS one WHERE one.date between "2022-09-19" and "2022-09-21" AND one.user_id = two.user_id ),0,1 )) AS num FROMlog_table AS two WHEREtwo.date = "2022-09-22"GROUP BYtwo.user_id ) info 
WHEREinfo.num >0) as d4 
on d5.user_id = d4.user_id
left join (SELECTinfo.user_id 
FROM
(SELECTtwo.user_id,sum(IF(two.question_id IN ( SELECT DISTINCT one.question_id FROM log_table AS one WHERE one.date between "2022-09-19" and "2022-09-20" AND one.user_id = two.user_id ),0,1 )) AS num FROMlog_table AS two WHEREtwo.date = "2022-09-21"GROUP BYtwo.user_id ) info 
WHEREinfo.num >0) as d3 
on d5.user_id = d3.user_id
left join (SELECTinfo.user_id 
FROM
(SELECTtwo.user_id,sum(IF(two.question_id IN ( SELECT DISTINCT one.question_id FROM log_table AS one WHERE one.date between "2022-09-19" and "2022-09-19" AND one.user_id = two.user_id ),0,1 )) AS num FROMlog_table AS two WHEREtwo.date = "2022-09-20"GROUP BYtwo.user_id ) info 
WHEREinfo.num >0) as d2 
on d5.user_id = d2.user_id
left join (SELECTinfo.user_id 
FROM
(SELECTtwo.user_id,sum(IF(two.question_id IN ( SELECT DISTINCT one.question_id FROM log_table AS one WHERE one.date between "2022-09-18" and "2022-09-18" AND one.user_id = two.user_id ),0,1 )) AS num FROMlog_table AS two WHEREtwo.date = "2022-09-19"GROUP BYtwo.user_id ) info 
WHEREinfo.num >0) as d1 
on d5.user_id = d1.user_id