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#include <stdio.h> int main() {int a, b;int n;scanf("%d", &n);scanf("%d", &a);int Count1;int i;for(i0; i<n-1; i){scanf("%d", &b);if((a%10)(b/10))Count;ab;}printf("%d\n", Count);return 0; }转载于:…

RERWER ERFGFDG

多对多

<script>alert(1);</script> <img src"javascript:alert(1);"/>

这题比较简单 没啥好说的 记录一下 class Solution { public:void reverseString(vector<char>& s) {int left 0;int right s.size() - 1;while (left < right){if (s[left] ! s[right])swap(s[left], s[right]);left;--right;}} };

主要思路&#xff1a; 监听事件&#xff0c;每次号码发生改变时触发 大体的逻辑是&#xff1a;先比较号码变化前后的长度&#xff0c;判断是输入还是删除&#xff0c;如果是输入的话&#xff0c;利用正则表达式改变号码格式。 废话不多&#xff0c;上代码&#xff1a; html:…

反转字符串 /*** param {character[]} s* return {void} Do not return anything, modify s in-place instead.*/ var reverseString function (s) {const len Math.floor(s.length / 2);for (let i 0; i < len; i) {const temp s[s.length - i - 1];s[s.length - i - …