Java---阶段项目----五子棋
- 需求说明
- 技术实现
- 棋盘制作
- 完整代码
需求说明
五子棋棋盘为一个10×10的方格，五子棋玩家共为两个(A,B)，A在棋盘上落子后，B再落子，依次往复，直到一方胜利或者棋盘空间用完为止，判断胜利的条件就是一条线或者斜线上同时存在A或者B的连续的5颗棋子
如图：
技术实现
静态变量：
- 语法：
public static 数据类型 变量名 = 变量值;
不加static的就是非静态变量
- 解释说明
静态变量只能定义在类中，不能定义在方法中。
静态变量可以在static修饰的方法中使用，也可以在非静态的方法中访问
主要解决在静态方法中不能访问非静态的变量。
public class study { //类//静态变量只能定义在类中，不能定义在方法中public static String name = "张三";public static void main(String[] args) { //方法System.out.println(name); //可以调用}
}
静态方法：
- 语法
public static 返回值类型 方法名(){}
- 解释说明
静态方法就相当于一个箱子，只是箱子里面放的是代码，需要用这些代码的时候，直接把箱子放在指定位置即可
public class study { //类public static void main(String[] args) { //方法show();}public static void show(){System.out.println("张三");System.out.println("男");System.out.println("20");}
}
输出：
张三
男
20
棋盘制作
1.制作棋盘
- 使用输入法中的制表符在控制台直接打印出棋盘，然后寻找落子位置的特征
- 利用二维数组重新制作棋盘
public class study {public static char[][] chess_map={{'┌','┬','┬','┬','┬','┬','┬','┬','┬','┐'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'└','┴','┴','┴','┴','┴','┴','┴','┴','┘'}};public static String row = "────";public static void main(String[] args) {System.out.println(" 0 1 2 3 4 5 6 7 8 9");for(int i=0;i<chess_map.length;i++) {//外层循环控制行System.out.print(i);for(int j=0;j<chess_map[i].length;j++){//内层循环控制列if(j==chess_map[i].length-1){//最后一行不打印——System.out.print(chess_map[i][j]);}else{System.out.print(chess_map[i][j]+row);}}System.out.println();if(i<chess_map.length-1){//排除最后一行System.out.println(" │ │ │ │ │ │ │ │ │ │");}}}
}
- 棋盘在玩家使用过程中会反复展示，需要使用方法来优化
把棋盘放在一个方法内，直接调用
2.落子
- 玩家A，B会交替落子
- 落子的位置必须是0~100之间的整数，且不能使用已经存在的棋子
public static char pieceA = '○';//玩家A的棋子public static char pieceB = '■';//玩家B的棋子public static void main(String[] args) {draw_map();int sum = chess_map.length*chess_map[0].length;Scanner sc = new Scanner(System.in);for(int i=0;i<sum;i++){System.out.println(i%2==0 ? "玩家A落子：":"玩家B落子：");int position;while(true){//保证落子成功if(sc.hasNextInt()){//判断Scanner中是否有输入的数据position = sc.nextInt();if(position >= 0 && position < sum){char currentpiece = (i%2==0) ? pieceA : pieceB;int row = position / chess_map.length;//位置除以棋盘数组长度得到行号int col = position % chess_map[0].length;//位置取模棋盘数组的总列数得到列号if(chess_map[row][col]==pieceA || chess_map[row][col]==pieceB) {System.out.println("该位置已经有棋子，请重新输入：");continue;}else {chess_map[row][col] = currentpiece;break;}}else{System.out.println("非法输入");}}else{System.out.println("非法输入");sc.next();//将Scanner中的数据取出来，防止死循环}}//落子成功后棋盘需要重新打印draw_map();}}
- 落子完成后，需要校验是否获胜
- 棋盘使用完毕还未分出胜负，需要提示
for (int m = 0; m < chess_map.length; m++) {for (int j = 0; j < chess_map[0].length; j++) {//第一种，水平方向boolean case1 = (j + 4 < chess_map[0].length)&& chess_map[m][j] == currentpiece&& chess_map[m][j + 1] == currentpiece&& chess_map[m][j + 2] == currentpiece&& chess_map[m][j + 3] == currentpiece&& chess_map[m][j + 4] == currentpiece;//第二种，垂直方向boolean case2 = (m + 4 < chess_map.length)&& chess_map[m][j] == currentpiece&& chess_map[m + 1][j] == currentpiece&& chess_map[m + 2][j] == currentpiece&& chess_map[m + 3][j] == currentpiece&& chess_map[m + 4][j] == currentpiece;//第三种，135°角boolean case3 = (i + 4 < chess_map.length)&& (j + 4 < chess_map[0].length)&& chess_map[m][j] == currentpiece&& chess_map[m + 1][j + 1] == currentpiece&& chess_map[m + 2][j + 2] == currentpiece&& chess_map[m + 3][j + 3] == currentpiece&& chess_map[m + 4][j + 4] == currentpiece;//第四种，45°角boolean case4 = (m > 4) && (j + 4 < chess_map[0].length)&& chess_map[m][j] == currentpiece&& chess_map[m - 1][j + 1] == currentpiece&& chess_map[m - 2][j + 2] == currentpiece&& chess_map[m - 3][j + 3] == currentpiece&& chess_map[m - 4][j + 4] == currentpiece;if (case1 || case2 || case3 || case4) {System.out.println(m % 2 == 0 ? "玩家A胜利" : "玩家B胜利");break outer;}}}i++;}if(i==100){System.out.println("平局");}
3.声音特效
- 为落子，非法落子及其获胜添加音效
需要准备文件
public static void playAudio(String fileName){URl url = Gobang.class.getResource(fileName);AudioClip clip = Applet.newAudioClip(url);clip.play();try{Thread.sleep(50L);}catch (InterruptedException e){}}
完整代码
import java.util.Scanner;public class study {public static char[][] chess_map={{'┌','┬','┬','┬','┬','┬','┬','┬','┬','┐'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'├','┼','┼','┼','┼','┼','┼','┼','┼','┤'},{'└','┴','┴','┴','┴','┴','┴','┴','┴','┘'}};public static String ro = "────";public static char pieceA = '○';//玩家A的棋子public static char pieceB = '■';//玩家B的棋子public static int i = 0;//总次数public static void main(String[] args) {draw_map();int sum = chess_map.length * chess_map[0].length;Scanner sc = new Scanner(System.in);outer:while(i<sum){System.out.println(i % 2 == 0 ? "玩家A落子：" : "玩家B落子：");char currentpiece = (i % 2 == 0) ? pieceA : pieceB;
// int position_row,position_col;int position;while (true) {//保证落子成功if (sc.hasNextInt()) {//判断Scanner中是否有输入的数据
// System.out.println("请输入行：");
// position_row = sc.nextInt();
// System.out.println("请输入列：");
// position_col = sc.nextInt();position = sc.nextInt();
// if(position_row >= 0 && position_row < chess_map.length && position_col>=0 && position_col < chess_map[0].length){if (position >= 0 && position < sum) {int row = position / chess_map.length;//位置除以棋盘数组长度得到行号int col = position % chess_map[0].length;//位置取模棋盘数组的总列数得到列号
// int row = position_row;
// int col = position_col;if (chess_map[row][col] == pieceA || chess_map[row][col] == pieceB) {System.out.println("该位置已经有棋子，请重新输入：");continue;} else {chess_map[row][col] = currentpiece;break;}} else {System.out.println("非法输入");}} else {System.out.println("非法输入");sc.next();//将Scanner中的数据取出来，防止死循环}}//落子成功后棋盘需要重新打印draw_map();for (int m = 0; m < chess_map.length; m++) {for (int j = 0; j < chess_map[0].length; j++) {//第一种，水平方向boolean case1 = (j + 4 < chess_map[0].length)&& chess_map[m][j] == currentpiece&& chess_map[m][j + 1] == currentpiece&& chess_map[m][j + 2] == currentpiece&& chess_map[m][j + 3] == currentpiece&& chess_map[m][j + 4] == currentpiece;//第二种，垂直方向boolean case2 = (m + 4 < chess_map.length)&& chess_map[m][j] == currentpiece&& chess_map[m + 1][j] == currentpiece&& chess_map[m + 2][j] == currentpiece&& chess_map[m + 3][j] == currentpiece&& chess_map[m + 4][j] == currentpiece;//第三种，135°角boolean case3 = (i + 4 < chess_map.length)&& (j + 4 < chess_map[0].length)&& chess_map[m][j] == currentpiece&& chess_map[m + 1][j + 1] == currentpiece&& chess_map[m + 2][j + 2] == currentpiece&& chess_map[m + 3][j + 3] == currentpiece&& chess_map[m + 4][j + 4] == currentpiece;//第四种，45°角boolean case4 = (m > 4) && (j + 4 < chess_map[0].length)&& chess_map[m][j] == currentpiece&& chess_map[m - 1][j + 1] == currentpiece&& chess_map[m - 2][j + 2] == currentpiece&& chess_map[m - 3][j + 3] == currentpiece&& chess_map[m - 4][j + 4] == currentpiece;if (case1 || case2 || case3 || case4) {System.out.println(m % 2 == 0 ? "玩家A胜利" : "玩家B胜利");break outer;}}}i++;}if(i==100){System.out.println("平局");}}public static void draw_map () {System.out.println(" 0 1 2 3 4 5 6 7 8 9");for (int i = 0; i < chess_map.length; i++) {//外层循环控制行System.out.print(i);for (int j = 0; j < chess_map[i].length; j++) {//内层循环控制列if (j == chess_map[i].length - 1) {//最后一行不打印——System.out.print(chess_map[i][j]);} else {System.out.print(chess_map[i][j] + ro);}}System.out.println();if (i < chess_map.length - 1) {//排除最后一行System.out.println(" │ │ │ │ │ │ │ │ │ │");}}}}
