通过返回的key值匹配字典中的value值

需求

页面中上面搜索项有获取字典枚举接口，table表格中也有根据key匹配字典中的value

方案一

在这里插入图片描述

需要做到的要求

这里上面下拉列表是一个组件获取的字典，下面也是通过字典匹配，所以尽量统一封装一个函数，每个组件保证最少变动
table表格中如果filters中更改,会获取多次接口，—使用闭包让只获取一次接口，节省性能
filter中又是必须同步函数，异步函数报错，所以不能使用async,await
最好请求接口之后存储起来下次直接拿不用请求了

综上

utils/dictionary.js

javascript">import { getDicValue } from '@/api/systemManage'
import store from '@/store'
/*** 获取字典数据* @param {Boolean} hasAllOption 是否包含全部选项*/
export function getDicValueList(dictClassCode, hasAllOption = true) {const dictionaryCache = store.state.dictionary.dictionaryCache || {}return new Promise((resolve, reject) => {let optionList = []if (dictionaryCache[dictClassCode]) {const dicList = JSON.parse(JSON.stringify(dictionaryCache[dictClassCode]))if (hasAllOption) {optionList = [ { value: '', label: '全部' }, ...dicList]} else {optionList = [...dicList]}resolve(optionList)} else {getDicValue(dictClassCode).then(response => {console.log('字典调用', dictClassCode)const dicList = response.value || []store.dispatch('dictionary/setDictionaryCache', { key: dictClassCode, value: dicList })if (hasAllOption) {optionList = [ { value: '', label: '全部' }, ...dicList]} else {optionList = [...dicList]}resolve(optionList)}).catch(error => {reject([])})}})
}/*** 获取字典数据并返回一个闭包函数* @param {string} dictClassCode 字典类代码* @param {string} noTitle 默认值，当找不到匹配项时返回* @returns {Promise<Function>} 返回一个闭包函数，该函数可以根据 value 获取 label*/
export async function getDicValueName(dictClassCode, noTitle = "--") {try {const response = await getDicValueList(dictClassCode, false)const listData = response || []return (value) => {let label = noTitlelistData.some(item => {if (item.value === value) {label = item.labelreturn true}})return label}} catch (err) {console.error(err)return (value) => noTitle}
}

下拉框组件

javascript">created () {this.getOptionLists()},getOptionLists() {if (this.dictClassCode) {getDicValueList(this.dictClassCode).then(res => {this.optionLists = res})} else {this.optionLists = this.options}},

table组件中

javascript"><span>{{ filterStateName(scope.row.state) }}</span>import { getDicValueName } from '@/utils/dictionary'created() {this.initDictionary()},methods: {
async initDictionary() {try {this.filterStateName = await getDicValueName('DC_DICTIONARY_STATE')} catch (error) {console.error('Failed to fetch dictionary:', error)this.filterStateName = (value) => '--'}},}

问题：但是这种因为一进页面这两个组件都是去获取字典，所以还是从接口拿的数据，会调用两次接口

方案二（建议）

方案：接下来优化可以通过路由导航预加载，先获取字典之后，在加载页面
router.js

javascript">// 预加载字典
export function preloadDictionary(dictClassCodeList) {const pList = []dictClassCodeList.forEach(dictClassCode => {const p = getDicValueList(dictClassCode)pList.push(p)})return Promise.all(pList)
}// 预加载字典
router.beforeEach((to, from, next) => {if(to.meta && to.meta.dictClassCodeList&& to.meta.dictClassCodeList.length > 0) {preloadDictionary(to.meta.dictClassCodeList).then(res => {next()})} else {next()}
})