题目：进制转换合集

#pragma once
#include<stdio.h>
#include<ctype.h>
#include<stdbool.h>
#include<string>/// <summary>
/// 将字符串表示的任意进制数转为十进制
/// </summary>
/// <param name="str">字符串</param>
/// <param name="base">进制基数</param>
/// <returns></returns>
long stringToDecimal(const char* str, int base) {long result = 0;int multiplier = 1;int len = strlen(str);//从字符串末尾开始解析for (int i = len - 1; i >= 0; i--) {char c = tolower(str[i]);//先将当前字符转为小写int digit = -1;//根据字符计算对应的值if (c >= '0' && c <= '9') { // 计算0-9的数字digit = c - '0';//将数字字符转为对应的十进制数字}else if (base == 16 && (c >= 'a' && c <= 'f')) {digit = c - 'a' + 10;//计算大于大于9小于f的字符对应的数字}else if (c < '0' || (c > '9' && base != 16) || (base == 16 && c > 'f')) {return 0;//出错}//检查是否在有效范围内if (digit >= base) {return 0;}//累加结果result += digit * multiplier;//从低位算，第一项均为1，第二项为base^1, 第三项为base^2 , ......multiplier *= base;}return result;}/// <summary>
/// 将十进制数字转为任意的r进制
/// </summary>
/// <param name="num">数字</param>
/// <param name="r">进制数</param>
void convertToBaseR(int num, int r) {int index = 0;char result[65];//假设转换后的数字不超过64位//处理num为0的情况if (num == 0) {printf("0\n");return;}while (num > 0) {int remainder = num % r;if (remainder < 10) {result[index++] = '0' + remainder;//余数小于10的转成0-9之间的支付}else {result[index++] = 'A' + (remainder - 10);//余数大于10的，将其转成A ~ Z之间的字符}num /= r;//更新num的值}result[index] = '\0';//添加字符串末尾结束符//打印for (int i = index - 1; index >= 0; index--) {printf("%c", result[i]);}printf("\n");
}