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依次遍历 不符合条件就反转

题目要干嘛 你就干嘛

#include <bits/stdc++.h>#define endl '\n' using namespace std;int main() {ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);	string s; cin >> s;string t; cin >> t;int ret = 0;for ( int i = 0; i < s.size(); ++i ){if ( s[i] != t[i]){  //不等 反转硬币 s[i] = s[i] == 'o' ? '*' : 'o';s[i + 1] = s[i + 1] == 'o' ? '*' : 'o';++ret;}}cout << ret << endl;return 0; 
}