文件名pyre.cpython-36.pyc，说明是在python3.6环境下编译的，要把pyc反编译成py

但是显示失败了，结合题的名字文件的应该是文件头部被破坏

把第一行改为33 0D 0D 0A 0C 63 4A 63 61 02 00 00 E3 00 00 00

之后就能反编译了，得到源码如下

python"># uncompyle6 version 3.8.0
# Python bytecode 3.6 (3379)
# Decompiled from: Python 3.6.0 (v3.6.0:41df79263a11, Dec 23 2016, 08:06:12) [MSC v.1900 64 bit (AMD64)]
# Embedded file name: pyre.py
# Compiled at: 2022-10-15 15:36:44
# Size of source mod 2**32: 609 bytes
from ctypes import *
from Crypto.Util.number import bytes_to_long
from Crypto.Util.number import long_to_bytesdef encrypt(v, k):v0 = c_uint32(v[0])v1 = c_uint32(v[1])sum1 = c_uint32(0)delta = 195935983for i in range(32):v0.value += (v1.value << 4 ^ v1.value >> 7) + v1.value ^ sum1.value + k[(sum1.value & 3)]sum1.value += deltav1.value += (v0.value << 4 ^ v0.value >> 7) + v0.value ^ sum1.value + k[(sum1.value >> 9 & 3)]return (v0.value, v1.value)if __name__ == '__main__':flag = input('please input your flag:')k = [255, 187, 51, 68]if len(flag) != 32:print('wrong!')exit(-1)a = []for i in range(0, 32, 8):v1 = bytes_to_long(bytes(flag[i:i + 4], 'ascii'))v2 = bytes_to_long(bytes(flag[i + 4:i + 8], 'ascii'))a += encrypt([v1, v2], k)enc = [4006073346, 2582197823, 2235293281, 558171287, 2425328816, 1715140098, 986348143, 1948615354]for i in range(8):if enc[i] != a[i]:print('wrong!')exit(-1)print('flag is flag{%s}' % flag)
# okay decompiling d:\pyre.cpython-36.pyc

由此得到解密代码：

python">#include<stdio.h>
#define  u_int unsigned int
int main()
{u_int enc[] = { 4006073346, 2582197823, 2235293281, 558171287,2425328816, 1715140098, 986348143, 1948615354 };u_int k[] = { 255, 187, 51, 68 };for (int i = 0; i < 8; i += 2){u_int delta = 195935983;u_int s1 = delta * 32;for (int j = 0; j < 32; j++){enc[i + 1] -= (enc[i] << 4 ^ enc[i] >> 7) + enc[i] ^ s1 + k[s1 >> 9 & 3];s1 -= delta;enc[i] -= (enc[i + 1] << 4 ^ enc[i + 1] >> 7) + enc[i + 1] ^ s1 + k[s1 & 3];}}char flag[32] = { 0 };for (int i = 0; i < 8; i++){flag[4 * i] = enc[i] >> 24;flag[4 * i + 1] = (enc[i] >> 16) ^ 0xFF000000;flag[4 * i + 2] = (enc[i] >> 8) ^ 0xFF000000;flag[4 * i + 3] = enc[i] ^ 0xFF000000;}for (int i = 0; i < 32; i++){printf("%c", flag[i]);}
}

得到：flag{Th1s_1s_A_Easy_Pyth0n__R3veRse_0}