继承与多态
继承
父子出现同名的成员问题
#include <iostream>using namespace std;
class Father{
public:string name;
protected:int pwd;
private:int money;
public:Father(){cout<<"Father::构造"<<endl;}Father(string n,int p,int m):name(n),pwd(p),money(m){cout<<"Father::有参"<<endl;}};
class Son:public Father{
public:int name;
};
class Test{
public:Father f;
};int main()
{Father father;Son son;Test test;cout<<"&son="<<&son.name<<endl;cout<<"&father="<<&son.Father::name<<endl;cout<<"&test="<<&test<<endl;cout<<"&test.f="<<&test.f<<endl;return 0;
}
关于继承中特殊成员函数
#include <iostream>using namespace std;
class Father{
public:string name;
protected:int pwd;
private:int money;
public:Father(){cout<<"Father::构造"<<endl;}Father(string n,int p,int m):name(n),pwd(p),money(m){cout<<"Father::有参"<<endl;}~Father(){cout<<"析构"<<endl;}Father(const Father & other):name(other.name),pwd(other.pwd),money(other.money){cout<<"Father::拷贝构造"<<endl;}Father&operator=(const Father&other){if(this!=&other){this->name=other.name;this->pwd=other.pwd;this->money=other.money;}cout<<"Father::拷贝赋值函数"<<endl;return *this;}void show(){cout<<"Father::name = "<<name<<endl;cout<<"Father::pwd = "<<pwd<<endl;cout<<"Father::money = "<<money<<endl;}};
class Son:public Father{private:string toy;
public:Son(){cout<<"Son::无参构造"<<endl;}~Son(){cout<<"Son::析构函数"<<endl;}Son(const Son& other):Father(other),toy(other.toy){cout<<"Son::拷贝构造函数"<<endl;}Son(string n, int p, int m, string t): Father(n, p, m), toy(t){cout<<"Son::有参构造"<<endl;}void show(){Father::show(); cout<<"toy = "<<toy<<endl;}};int main()
{Son s1("xx",123,5,"a");s1.show();Son s2(s1);s2.show();return 0;
}
练习:将图形类的获取周长和获取面积函数设置成虚函数,完成多态 再定义一个全局函数,能够在该函数中实现:无论传递任何图形,都可以输出传递的图形的周长和面积
#include <iostream>using namespace std;class Shape{double perimeter;double area;
public:Shape(){cout<<"Shape::无参"<<endl;}Shape(const Shape & other):perimeter(other.perimeter),area(other.area){cout<<"拷贝构造函数"<<endl;}Shape & operator =(const Shape & other){if(this==&other){return *this;}perimeter=other.perimeter;area=other.area;return *this;}~Shape(){cout<<"shape::析构"<<endl;}virtual void show(){cout<<"perimeter"<<perimeter<<endl;cout<<"area"<<area<<endl;}double getPer(){return perimeter;}double getArea(){return area;}void setPer(double p){this->perimeter=p;}void setArea(double a){this->area=a;}};class Rectangle:public Shape
{
private:int wide;int high;
public:Rectangle(){}Rectangle(int w,int h):wide(w),high(h){}~Rectangle(){}Rectangle(const Rectangle &other):Shape(other),wide(other.wide),high(other.high){}Rectangle & operator= (const Rectangle &other){if(this != &other){Shape::operator=(other);this->wide = other.wide;this->high = other.high;}return *this;}void show(){cout<<"矩形 长:"<<wide<<" 宽:"<<high<<endl;cout<<"perimeter"<<get_perimeter()<<endl;cout<<"area"<<get_area()<<endl;}int get_perimeter(){this->setPer( 2.0*(wide+high));return Shape::getPer();}int get_area(){this->setArea( 1.0*wide*high);return Shape::getArea();}
};
class Circle:public Shape
{
private:int radius;
public:Circle(){}Circle(int r):radius(r){}~Circle(){}Circle(const Circle &other):Shape(other),radius(other.radius){}Circle & operator= (const Circle &other){if(this != &other){Shape::operator=(other);this->radius = other.radius;}return *this;}void show(){cout<<"圆形 半径:"<<radius<<endl;cout<<"perimeter"<<get_perimeter()<<endl;cout<<"area"<<get_area()<<endl;}int get_perimeter(){this->setPer( 2*3.14*radius);return Shape::getPer();}int get_area(){this->setArea( 3.14*radius*radius);return Shape::getArea();}};
void display( Shape & shape){shape.show();
}
int main()
{Rectangle rec(10,20);Circle cir(10);display(rec);display(cir);return 0;
}
手动实现一个循环顺序队列
#include<iostream>
using namespace std;
class myqueue{
int front;
int rear;
int maxSize;
int *data;public:
myqueue():front(0),rear(0),maxSize(0),data(NULL){}
myqueue(int k):front(0),rear(0),maxSize(k+1),data(new int[k+1]){
cout<<"有参构造"<<endl;
}
myqueue(const myqueue & other):front(other.front),rear(other.rear),maxSize(other.maxSize),data(new int[other.maxSize]){memcpy(data,other.data,sizeof(int)*maxSize);
}
myqueue & operator = (const myqueue &other){if(this==&other) return *this;front=other.front;rear=other.rear;maxSize=other.maxSize;int *temp=new int[maxSize];delete [] data;data=temp;return *this;
}int myfront(){return data[front];
}
int back(){if(empty()){return -1;}return data[(rear-1+maxSize)%maxSize];
}
bool empty(){return rear==front;
}
bool full(){return (rear+1)%maxSize==front;
}
int size(){return (front-rear+maxSize)%maxSize;
}
bool push(int val){
if(full()) return false;
data[rear]=val;
rear=(rear+1)%maxSize;
return true;
}
int pop(){if(empty()) return -1;int res=data[front];front=(front+1)%maxSize;return res;
}
void show(){for(int i=front;i!=rear;i=(i+1)%maxSize){cout<<data[i]<<" ";}cout<<endl;
}
};int main(){myqueue a(5);a.push(1);a.push(2);a.push(3);a.push(4);a.push(5);a.pop();a.push(6);a.show();
}