具体可实现的效果例如：

数据格式：

具体代码实现：

javascript">     /*** 获取当前日期的第一个周一是哪天* @params date - 'YYYY-MM'*/function getMonthFirstWeekDay(date) {let year = new Date(date).getFullYear();let month = new Date(date).getMonth();for (let week = 1; week < 8; week++) {if (new Date(`${year}-${month + 1}-${week}`).getDay() === 1) {return week;}}}/*** 获取start日期到end日期的周集合* @params start - 'YYYY-MM'* @params end - 'YYYY-MM'*/function getAllWeeks(start, end) {if (!start) return [];// 结束日期try {let endDate = end ? new Date(end) : new Date();let endYear = endDate.getFullYear();let endMonth = endDate.getMonth() + 2;if (endMonth > 11) {endMonth = "1";endYear++;}end = `${endYear}-${endMonth}`;const weeks = []; // 周数组let firstWeek = getMonthFirstWeekDay(start); // 周几let firstDate = `${start}-${firstWeek}`; // 第一周日期let endTimestamp = new Date(end).getTime(); // 不超过最后月份时间戳let prevTimestamp = new Date(firstDate).getTime(); // 第一周时间戳let oneDay = 24 * 60 * 60 * 1000; // 一天的时间戳偏移量while (prevTimestamp < endTimestamp) {let prevDate = new Date(prevTimestamp);let nextDate = new Date(prevTimestamp + oneDay * 6);let prevY = prevDate.getFullYear();let prevM = prevDate.getMonth() + 1;let prevD = prevDate.getDate();let nextY = nextDate.getFullYear();let nextM = nextDate.getMonth() + 1;let nextD = nextDate.getDate();weeks.push([{year: prevY,month: prevM,day: prevD,ymd: `${prevY}-${prevM}-${prevD}`,ym: `${prevY}-${prevM}`,md: `${prevM}-${prevD}`,},{year: nextY,month: nextM,day: nextD,ymd: `${nextY}-${nextM}-${nextD}`,ym: `${nextY}-${nextM}`,md: `${nextM}-${nextD}`,},]);prevTimestamp += oneDay * 7;}return weeks;} catch (error) {return [];}}// 使用示例// 全部周const weeks = getAllWeeks("2023-12", "2024-01");console.log("weeks:", weeks);// 按月分组const weeksByMonth = Object.groupBy(weeks, (op) => op[0].ym);console.log("weeksByMonth:", weeksByMonth);// 按年分组const weeksByYear = Object.groupBy(weeks, (op) => op[0].year);console.log("weeksByYear:", weeksByYear);

需求简要描述一下吧

就是获取某个时间范围内，生成月报周报，第一个周报为时间范围当月的第一周，跨周则依然归属于当月，跨周的下个周一才归属下个月。生成这样的周报月报下拉选项。